Given a differential amplifier with a gain of 1,000,000 and inputs of 0.2 uV and 0.8 uV, what is the output?

Prepare for the ABRET CNIM Exam. Use flashcards and multiple choice questions, each with explanations. Ready yourself for the exam day!

To determine the output of a differential amplifier, you first need to calculate the differential voltage between the two input signals. In this case, the inputs are 0.2 microvolts (uV) and 0.8 microvolts (uV).

The differential voltage (V_d) is calculated by subtracting the smaller input from the larger input:

V_d = V_in(+) - V_in(-) = 0.8 uV - 0.2 uV = 0.6 uV

Next, to find the output voltage (V_out) of the differential amplifier, you multiply the differential voltage by the gain of the amplifier. Here, the gain is given as 1,000,000:

V_out = Gain × V_d = 1,000,000 × 0.6 uV = 600,000 uV or 0.6 volts.

Therefore, the correct answer is that the output voltage of 0.6 uV aligns with the calculations based on the inputs and the specified gain.

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