What is the frequency of a signal if the interval between each cycle of the signal is 0.3 ms in a 30 ms sweep?

Prepare for the ABRET CNIM Exam. Use flashcards and multiple choice questions, each with explanations. Ready yourself for the exam day!

To determine the frequency of a signal based on the interval between each cycle, you can use the relationship between frequency and period. The frequency (f) is the reciprocal of the period (T), which is the time it takes for one complete cycle to occur.

Here, the interval between each cycle is provided as 0.3 milliseconds (ms). First, convert the milliseconds to seconds for calculation purposes:

0.3 ms = 0.3 × 10^-3 seconds = 0.0003 seconds.

The frequency can be calculated using the formula:

f = 1/T.

Substituting the period into the equation:

f = 1/0.0003.

Calculating this gives:

f = 3333.33 Hz, or approximately 3.33 kHz.

Since this value doesn't match any of the multiple-choice answers directly, it's important to examine the context of the question. If the sweep duration is mentioned as 30 ms, it implies that during that entire duration, there are multiple cycles occurring. To find the number of cycles during this sweep, take the sweep duration and divide it by the cycle interval.

Number of cycles = Sweep duration / Cycle interval

= 30 ms / 0.3

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